My problem (make it simple) is not accepted ,what is wrong?

[adm2215]

include

int main()
{
int c,i,a,b,count=0;;
scanf("%d",&c);
for(i=1;i<=c;i++)
{
scanf("%d/%d",&a,&b);
if(a<=b && 1<=a && b<=1000000)
{
count++;
solve(a,b,count);
}
else{return 0;}
}
return 0;
}

solve(int d,int e,int c)
{
for(int j=9;j>=2;j--)
{
if(d%j==0 && e%j==0)
{
d=d/j;
e=e/j;
}
}
printf("\nCase %d: %d/%d",c,d,e);
}

[hoang2711997]

1

[hoang2711997]

2131231231231231aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

[tjm]

Try this test case (common divisors could be different than just 2..9):

2
13/13
41/697

Print a newline after each test case, not before.

If you validate input, then exit with non-zero exit code in case of failure. Otherwise it is quite hard to distinguish between say mistake in input condition validation and wrong answer produced elsewhere.

[adm2215]

thanks !!
changes i made
- kept \n after output
-took divisors between 1 and 5000