I am doing the programme correctly but it says its uncorrect

[ipatios]

the problem was: Life, the Universe, and Everything
my code on c++ is:
#include <stdio.h>
int main()
{
int i,q,n,num[1000];

//printf("\ninput:\n");
for(i=0; i<=5-1; i++)
{
 scanf("%d",&num[i]);

 	
 }

//printf("\noutput:\n");
i=0;
	  while(num[i]!=42)
 {
 printf("\n%d\n",num[i]);
 i++;
}

}

[pwojszepielak]

1. too many “\n” in the output
2. You do not need that “for” at all
3. you do not need array

[ipatios]

i dont get it and then what do i do ?
does the numbers need to be fixed ,and if i dont need an array then how i do it , the “\n” is for calisthetics purposes

[pwojszepielak]

1. Judge program do not cares about “calisthetics purposes”
2. You need one instruction while.
3. You need only varible num
   example pseudocode
   scan for num
   while (condition){
   print num and \n
   scan for num
   }