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ipatios
Sep '20

the problem was: Life, the Universe, and Everything
my code on c++ is:
#include <stdio.h>
int main()
{
int i,q,n,num[1000];

//printf("\ninput:\n");
for(i=0; i<=5-1; i++)
{
 scanf("%d",&num[i]);

 	
 }

//printf("\noutput:\n");
i=0;
	  while(num[i]!=42)
 {
 printf("\n%d\n",num[i]);
 i++;
}

}

  • created

    Sep '20

  • last reply

    Sep '20
  • 3

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pwojszepielak
Sep '20
1
  1. too many “\n” in the output
  2. You do not need that “for” at all
  3. you do not need array
ipatios
Sep '20

i dont get it and then what do i do ?
does the numbers need to be fixed ,and if i dont need an array then how i do it , the “\n” is for calisthetics purposes

pwojszepielak
Sep '20
  1. Judge program do not cares about “calisthetics purposes”
  2. You need one instruction while.
  3. You need only varible num
    example pseudocode
    scan for num
    while (condition){
    print num and \n
    scan for num
    }