when i run the following code i get result as wrong answer
can any1 plz tell me whats wrong or what cases i am missing ?
#include<stdio.h>
int main(void)
{
int cases,i,x,y,j;
int value[30000];
scanf("%d",&cases);
for(i=0;i<cases;i++)
{
scanf("%d %d",&x,&y);
/* all the following conditions result in "No Number" */
/* 1.when y > x
2.when x is odd & y is even or vice versa
3.when x>2 and y=0
*/
if(y>x || (x%2!=0 && y%2==0) || (x%2==0 && y%2!=0 ) || (x>2 && y==0))
value[i]=-1; /* a flag to indicate "No Number" */
else
{
if(x==y && ((x%2)==0)) /* when both same and even */
value[i]=2*x;
else if(x==y && ((x%2)!=0)) /* when both same and odd */
value[i]=(2*x)-1;
else if(x%2==0 && y%2==0) /* when both even and different */
value[i]=x+y;
else if(x%2!=0 && y%2!=0) /* when both odd and different */
value[i]=x+y-1;
}
}
/* output begins */
printf("\n");
for(j=0;j<i;j++)
{
if(value[j]==-1)
printf("No Number\n");
else
printf("%d\n",value[j]);
}
return 0;
}
i'd be grateful to the person who helps
thanks !!
