Dec 2008
1 / 4
Dec 2008
Jan 2018
abhijith
Dec '08

when i run the following code i get result as wrong answer
can any1 plz tell me whats wrong or what cases i am missing ?

#include<stdio.h>
int main(void)
{
  int cases,i,x,y,j;
  int value[30000];
  scanf("%d",&cases);
  for(i=0;i<cases;i++)
  {
    scanf("%d %d",&x,&y);
    /* all the following conditions result in "No Number" */
    /* 1.when y > x
       2.when x is odd & y is even or vice versa
       3.when x>2 and y=0
    */
    if(y>x || (x%2!=0 && y%2==0) || (x%2==0 && y%2!=0 ) || (x>2 && y==0)) 
      value[i]=-1;   				            /* a flag to indicate "No Number"       */
    else
    {
      if(x==y && ((x%2)==0))          /* when both same and even */
       value[i]=2*x;  
      else if(x==y && ((x%2)!=0))     /* when both same and odd */
        value[i]=(2*x)-1;
      else if(x%2==0 && y%2==0)       /* when both even and different */
        value[i]=x+y;
      else if(x%2!=0 && y%2!=0)       /* when both odd  and different */
        value[i]=x+y-1;
    }
  }
  /* output begins */
  printf("\n");
  for(j=0;j<i;j++)
  {
    if(value[j]==-1)
     printf("No Number\n");
    else
     printf("%d\n",value[j]);
  }
  return 0;
}

i'd be grateful to the person who helps

thanks !!

  • created

    Dec '08

  • last reply

    Jan '18
  • 3

    replies

  • 747

    views

  • 3

    users

TripleM_sof
Dec '08

There are a lot more cases where there is no number.. how about (10001,1)?

9 years later
kindacoder
Jan '18

Take a pen and Draw the diagram and look for logic:- It will click sure ::slight_smile:
#include
using namespace std;

int findTheNumber(int t){

int a,b,sub;
while(t){

  ///enter both the numbers-
    cin>>a>>b;
    sub=a-b;

///check the numbers odd or even:-

///Conditions:-
if((a%2)==0 && (b%2)==0 && sub==0 && a<=10000 && b<=10000){
cout<<a+b<<endl;
}
else if((a%2)==1 && (b%2)==1 && sub==0 && a<=10000 && b<=10000){
cout<<a+b-1<<endl;
}
else if((a%2)==0 && (b%2)==0 && sub==2 && a<=10000 && b<=10000){
cout<<a+b<<endl;
}
else if((a%2==1) && (b%2)==1 && sub==2 && a<=10000 && b<=10000){
cout<<a+b-1<<endl;
}
else{
cout<<“No Number”<<endl;
}

t--;

}

}
int main(){
int t;
cin>>t;
findTheNumber(t);

return 0;
}
`