I believe there is no need to discover the password, but rather, we should use the knowledge brought to us by the encrypted file, that is, the algorithm CRC32, the length of the message and the size of the file... I just don't know how to relate all that.
In the same way, I don't know what to do in the images problems, I mean, What are they asking? What are we looking for there?
i dont find zooming in and out a computer image healthy
and for the problem 10s picture
look to the picture properties
there are:
Number 758932
and
spoj.pl/content/turbo:032948.gif4
but i couldnt solve it, are they solveable in current contest?
also a note to the admin, i think answer.zip s password should be updated
You don't have to do that. If you can can handle the normal print variations without having to zoom in/out, you can do the same if it's on a computer screen. In any case, you can easily turn the brightness down if the screen hurts to look at (although this is only really a problem with CRTs.)
It's also possible to obtain the answer using Graphic editing software (although this basic method won't work on more complex versions of that image.)
hello,
I'm getting a little desperate with this one. I found a pattern:
v( 1 ) = v( 2^0 ) = 2
v( 2 ) = v( 2^1 ) = 3
v( 4 ) = v( 2^2 ) = 4
v( 8 ) = v( 2^3 ) = 5
v( 16 ) = v( 2^4 ) = 6
v( 32 ) = v( 2^5 ) = 7
Therefor it seems that v(2^x) = x+2, but when i submit 1002 for v(2^1000) I'm getting wrong answer. żAm I taking a wrong aproach or could it be that '^' in this case stands for bitwise operator XOR and we have to find v(1002)?
Thanks...
What's the method of determining the password for problem 2? I've tried a variety of tactics (e.g. guessing "password", using the filename as password, file size, and so on), but none of these had any result.
I can eventually figure out the other problems in PCV2, but bruteforcing the password didn't help me.