struct s{
double a;
char b;
double c;
int d;
};
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Aug '16last reply
Aug '16- 3
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This is because of Padding. Depending on the machine the word size may vary, your machine has a word size of 4 bytes meaning it would pad the extra number bytes for each data entry to be able read word chunks while performing operations.
double a; 8 Bytes ( No Padding Required as multiple of 4 )
char b; ( 1 Bytes , Requires 3 Bytes of Padding )
double c; 8 bytes ( No Padding required )
int d; ( 4 Bytes )
8 + 1 + 3 + 8 + 4 = 24
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