[quote="noix"]

#include <iostream>
int main(void) {
	char c, d=10;
	while(std::cin.get(c) && (c!='2' || d!='4') && std::cout.put(d)) 
		d=c;
}

[/quote]
This TEST solution is wrong, isn'it?
In case of input 8, 99, 4, 2, 10, 42, 3 it will output 8, 99.
I see that it's enough that it works for the test case, but as example answer it is not the best...

I agree it's not the best as an demonstrative example, but it does solve the problem exactly as specified. If you try the input you mentioned, you'll see it outputs the correct answer, not what you said it would.

I did

#include <stdio.h>
int main(void){
   int Input = 0;
   scanf("%d",&Input);
   while(Input != 42){
      printf("%d\n" , Input);
      scanf("%d",&Input);
      }
   return 0;
   }

simple straight forward and easy to read. Now fi I could just get my PRIME1 code to run in the alloted time...

can someone say what is the problem here.
JUDGE shows wrong answer

#include<iostream.h>
int main()
{
 int a;
 cin>>a;
 while(a!=42)
 {
             cout<<a;
             cin>>a;
 }
 return 0;
}

The correct answer for the sample input is

1
2
88

Your answer:

1288

Your solution is not correct even for the sample input.

[bbone=CPP,9]#include
using namespace std;

int main()
{
int x;
while(scanf("%d", &x) && x != 42)
printf("%d\n", x);
return 0;
}

[/bbone]

Ok i've manged to find a solution but when i submit it i got wrong answer even though it's doing what it's supposed to do

#include <iostream>
#include <stdio.h>
using namespace std;
int main()
{
	int x;
	do 
	{
		scanf ("%d", &x);
		printf (" %d \n", x);
	}
	while (x != 42);
return 0;
}

so what i'm doing wrong?

do-while is an exit control loop. it will first print the value and after that checks whether the entered value is terminating one i.e 42 or not. check you code for test cases.

I'm a bit puzzled. Because I fail to see where is the mistake in my code. Could anyone give me a hint?

#include <iostream>
using namespace std;
int main(void) {
 int a=0;
  while (a != 42){
  cin >> a;
  cout << a << endl;
  }
return 0;   
}

The solution should not print out 42. Yours will.

I'm still not sure what the questions actually asking. What's the number of inputs that our program has to take? Is it just five indicated by the example?

The number of inputs is undefined. Read until match.

#include <iostream>
using namespace std;
int main()
{
int size = 0;
int n[size];
do
	{
	cin>>n[size];
	size++;
	}while(n[size-1] != 42);
cin>>n[size];
for(int i = 0; i < (size-1); i++)
	{
		cout<<n[i]<<endl;
	}
return 0;
}

Hello everyone,
When i compile it it outputs the correct answer, however judge points me out to a runtime error (SIGSEGV).
What is wrong with the code then?
Thanks in advance, and glad to join this community.

When you declared n size was equal to zero, so n has zero elements. c and c++ don't check array bounds, they only throw errors when the program tries to access illegal memory (memory outside the defined space for the program).

For this problem the number of inputs are undefined. There could be ten, there could be a million. The amount doesn't matter.

Input a number. If it's 42 stop. Otherwise, output the number. Repeat.

I'm sorry this is actually my first program in C++. I've done this program in pascal before, and i just 'translated' in C++. The sample input and output works, but time limit exceeds. Am i doing something wrong? It works fine on Ideone.

#include <iostream>
using namespace std;
int main ()
{
  int a, b;
  bool c;
  c=false;
  while (true)
  {
        cin >> b;
        if (b == 42)
           c = true;
        else if (c == false)
            cout << b << "\n";      
  }
  return 0;
}

while(true) will never terminate. This code will not have run correctly on ideone.

I write this code and got pass in test.
The common mistake every one do in the beginnign is they actually put some helping text on cout to tell others what to do which is not needed.

#include <iostream>
using namespace std;
int main(){
    int x=0;
    cin >> x;
      while(x != 42){
              if (x <=99){
                 cout << x <<endl;
                 cin >> x;
                 }else {
                       cin >> x;
                 }
      }
}

my code is given below...my problem is just about the termination of input when i enter blank or simply press the return key...i appreciate any help..thanks alot!!

include

include

include

using namespace std;

main()
{
int input;
vectorv;
while(scanf ( "%d", &input ) == 1 )
{
//cin>>input;
if(!input)
break;
else
v.push_back(input);

}
vector<int>::iterator i;
for(i=v.begin();i<v.end();i++)
{
    if(*i!=42)
    cout<<*i<<endl;
    else break;
}

}