I write this code and got pass in test.
The common mistake every one do in the beginnign is they actually put some helping text on cout to tell others what to do which is not needed.

#include <iostream>
using namespace std;
int main(){
    int x=0;
    cin >> x;
      while(x != 42){
              if (x <=99){
                 cout << x <<endl;
                 cin >> x;
                 }else {
                       cin >> x;
                 }
      }
}

my code is given below...my problem is just about the termination of input when i enter blank or simply press the return key...i appreciate any help..thanks alot!!

include

include

include

using namespace std;

main()
{
int input;
vectorv;
while(scanf ( "%d", &input ) == 1 )
{
//cin>>input;
if(!input)
break;
else
v.push_back(input);

}
vector<int>::iterator i;
for(i=v.begin();i<v.end();i++)
{
    if(*i!=42)
    cout<<*i<<endl;
    else break;
}

}

stackoverflow.com/questions/1118 ... ate-an-eof25

i'm having the same "wrong answer". I don't know what's wrong! i get the right output! D:

#include <iostream>
using namespace std;
int main() {
int n, n2, n3, n4, n5;
cin>>n;
cin>>n2;
cin>>n3;
cin>>n4;
	switch(n4==42)
	{
		break;
		case 1:
			cin>>n5;
			cout<<n<<endl;
			cout<<n2<<endl;
			cout<<n3<<endl;
		break;
}
}

The "sample input" is not the only test case that your code will be tested on.

Some other test cases:

42

1
2
3
4
4
5
5
6
7
8
9
42
12
12
13

include

include

void main()
{ int n;
while(1)
{ cin>>n;
if(n==42)
break;
cout<<"\n"< }
getch();
}

this is the code which i wrote but it shows a compilation error.can someone please tell me what is wrong with this code?

Conio is not in the c standard library.

include

int main()
{ int n;
while(1)
{ cin>>n;
if(n==42)
break;
cout<<"\n"<}
return;
}

this is the edited code but this is also not working.it shows a compilation error.Could someone please give a sample code in c++ which will be accepted by spoj because when i compile it in my compiler then it shows no error.

If you click on compilation error it should give you more info. cin does not exist in the namespaces that you are using. Either use std::cin or at the top, after your includes,put:

using namespace std;

Please use code tags when posting code.

#include<iostream>
CODE: SELECT ALL
using namespace std;
int main()
{ int n;
while(1)
{ cin>>n;
if(n==42)
break;
cout<<"\n"<<n<<"\n";
}
return 0;
}

these are the errors it is showing after the correction
prog.cpp:2: error: function definition does not declare parameters
prog.cpp: In function 'int main()':
prog.cpp:7: error: 'cin' was not declared in this scope
prog.cpp:10: error: 'cout' was not declared in this scope

CODE: SELECT ALL

int number;

while(true)
{
cin >> number;
if(number == 40)
break;
cout << number;
}

}
dainik bhasker5

sir i am now working in dev c++ 4.9.9.2 and in which language i should summit my solution there is no option for this language

which compiler i should choose here i know coding in c++4.9.9.2

gcc.gnu.org/26

include

include

int main()
{
int s;
for(;
{
cin>>s;
if (s!=42)
cout<else
break;
}
return 0;
}

The SPOJ judge shows compilation error and I'm not able to figure it out.

If you click on where it says compilation error it will show what the compilation error is.

include

using namespace std;
int main()
{
int i,n,a[20];
cout<<"How Many Numbers Do u want to use as input :- ";
cin>>n;cout< for( i=0;i {
cin>>a[i];
}
cout<<"\nHere your output:- ";
for( i=0;i {
if(a[i]!=42)
cout<<" " < else if(a[i]==42)
break;
}
}
i hv written the prgrm using array 1st u hv to give all the no that u want to use as input & then it gives u the output as mentioned in the qstn, so where am i wrng??

include

int main(void)
{
int n,c=0,i;
int a[c];
printf(" input \n");
while(1)
{
scanf("%d",&n);
a[c]=n;
if(a[c]==42)
break;
c++;
}
printf("OUTPUT \n");
for(i=0;i printf("%d \n",a[i]);
return 0;

i ran this code but its giving wrong answer .please help me to correct this code.I am not getting my mistake
}