I'm having a similar problem and submitted following solution. When I ran it on http://ideone.com/22 it worked fine but still SPOJ saying it as wrong answer

Please correct me if anything wrong in my solution.

compiled with C++ 5.1

int main() {
	
	int i;
	std::cout<<"Enter your input number (42 is for exit)"<<endl;
	do
	{
		std::cin>>i;
		if( std::cin.fail() )
		{
			std::cout<<"Wrong input, numeric numbers only accepts"<<endl;	
		}
		else
		{
			std::cout<<i<<endl;
		}
	}while(42 != i);

	std::cout<<"Successfully exiting"<<endl;
	return 0;
}

Everything that you output is considered for the solution.

This line alone is enough to cause your wrong answer:

std::cout<<"Enter your input number (42 is for exit)"<<endl;

Only output what is required.

Thanks leppyr64

include

using namespace std;
int main()
{
int a;
while(1)
{
cin >>a;
if(a==42)
break;
else
cout <}
}

it shows compilation error but it works fine on my laptop

Simple solution in C++

include

include

using namespace std;

int main(){
int a[1000];
for(int i=0;i<1000;i++){
cin>>a[i];
}
for(int i=0;i<1000;i++){
if(a[i]!=42)
cout< else
break;
}
return 0;
}

My solution doesn't pass your tests. It compiles on my local system and seems to satisfy the requirements. I am using mingw492_32 compiler on my computer.

Question: How do I wrap this in a code block where it picks up my includes and angle brackets accurately?

(pound symbol)include < iostream>
(pound symbol)include < list>
using namespace std;

int main(void) {
int val;
list< int> array;

cout << "Input:" << endl;
while (true) {
    cin >> val;
    if (val > 99 || val < -99)
        continue;
    if (val == 42)
        break;
    array.push_back(val);
}
cout << "\n\nOutput:" << endl;
for (list<int>::iterator iter = array.begin(); iter != array.end(); iter++)
    cout << *iter << endl;
return 0;

}

Please keep in mind that this is my first day working with c++ (or any language). Having only a limited knowledge of using the iostream header, this is what I came up with:

#include <iostream>
using namespace std;

int main()
{
	int a;
	cin >> a;
	
	while (a != 42)
	{
		cout << a << endl;
		cin >> a;
	}

	return 0;
}

...and it works ...

It would better to use "using namespace std;" after header file.While loop is used for repeatation that we do not know the limit how times the loop will continue.It is better to use control statements such as" if , if else or switch case" for conditions.

Any help? "Wrong answer"

include

include

//void read();
using namespace std;

int main() {

//read();

int number=0;
std::fstream in;
std::fstream out;
in.open("data.txt");
out.open("output.txt");

if (in.good()) {
	in >> number;

	while (number != 42) {
		out << number << endl;
		in >> number;
		
	}
}



return 0;

}

This code gets accepted on CodeChef but it's saying "Wrong Answer" on SPOJ. If anyone can figure out what am I doing wrong. Help would be greatly appreciated.
`#include < iostream >
using namespace std;

int main() {
int x;
while(cin>>x ){

	if(x==42)
		break;
	cout<<x<<endl;

}
return 0;

} `

Can someone say what is the problem here?
Judge shows wrong answer:

#include<iostream>
using namespace std;

int main (){
	int number;
	freopen("index.txt","r", stdin );
	cin>>number;
	int P[number-1];
	for(int i=0;i<number;i++){
		cin>>P[i];
		if(P[i] == 42)
			break;
			cout<<P[i]<<'\n';
	}
}

hi what is the problem in this code.?
#include
using namespace std ;
int main()
{
int n[5],i;
for (i=0; i<=5;i++){
cin>>n[i];
}
for (i=0; i<=5;i++){
if (n[i]==42)
break;
else{
cout<<n[i]<<endl;
}
}
return 0;

}

Why it’s wrong?
#include
using namespace std;

int main()
{
int i,j,k,l,num[1000];
cout<<“Enter how many numbers you want to add:”;
cin>>i;
for(j=0;j<i;j++){
cin>>num[j];
if(num[j]==42){
break;
}
cout<<num[j]<<endl;
}
}

This text doesn’t appear in the sample output given in the problem, so you shouldn’t write it either.

The problem doesn’t say there will be 1000 numbers or or fewer, so it’d be better if you didn’t assume it.

#include<iostream>
#include <list>
#include <iterator>
using namespace std;

void outputNumber(list <int> g){
    list <int> :: iterator it;
    for(it = g.begin(); it != g.end(); ++it) {
        if(*it==42){
            break;
        }else{
            cout<<*it<<endl;
        }
    }
}

int main(){
    int myints[] = {1,2,88,42,99};
    std::list<int> testInputs (myints, myints + sizeof(myints) / sizeof(int) );
    std::cout << "The contents of the tested inputs are: ";
  for (std::list<int>::iterator it = testInputs.begin(); it != testInputs.end(); it++)
    std::cout << *it << ' ';

  std::cout << '\n';
    outputNumber(testInputs);
    return 0;

}

my codes have output the correct answers, but the compiler does not accept it…

The problem in the code lies in the while loop condition , i am not able to end taking the input, help!!
#include
#include<stdlib.h>
using namespace std;
int main()
{
int x[100],n=0,i=0;
while(cin>>n)
{

	x[i]=n;
	i++;
}
for(int j=0;j<=i;j++)
{
	if(x[j]==42) exit(15);
	else
	std::cout<<x[j]<<endl;
}
return 0;

}