Solution to TEST in C++

[srinivas_09]

Thanks leppyr64

[mack123]

i have the same problem,but i cant seem to figure out the answer.

[mack123]

include

using namespace std;
int main()
{
int a;
while(1)
{
cin >>a;
if(a==42)
break;
else
cout <}
}

it shows compilation error but it works fine on my laptop

[kukis243]

Hi, you are using else. You're supose to stop the outstream after reading numer 42.
Second is that can see cout<, that is probably why.

Good luck.

P.S. There's a good answer with the code above.

[brijeshjain13]

Simple solution in C++

include

include

using namespace std;

int main(){
int a[1000];
for(int i=0;i<1000;i++){
cin>>a[i];
}
for(int i=0;i<1000;i++){
if(a[i]!=42)
cout< else
break;
}
return 0;
}

[caolan]

My solution doesn't pass your tests. It compiles on my local system and seems to satisfy the requirements. I am using mingw492_32 compiler on my computer.

Question: How do I wrap this in a code block where it picks up my includes and angle brackets accurately?

(pound symbol)include < iostream>
(pound symbol)include < list>
using namespace std;

int main(void) {
int val;
list< int> array;

cout << "Input:" << endl;
while (true) {
    cin >> val;
    if (val > 99 || val < -99)
        continue;
    if (val == 42)
        break;
    array.push_back(val);
}
cout << "\n\nOutput:" << endl;
for (list<int>::iterator iter = array.begin(); iter != array.end(); iter++)
    cout << *iter << endl;
return 0;

}

[iwant2learn]

Please keep in mind that this is my first day working with c++ (or any language). Having only a limited knowledge of using the iostream header, this is what I came up with:

#include <iostream>
using namespace std;

int main()
{
	int a;
	cin >> a;
	
	while (a != 42)
	{
		cout << a << endl;
		cin >> a;
	}

	return 0;
}

[daft_wullie]

...and it works ...

[sayed015]

i think this one is better , much much better approach to solve this code

[rakp]

It would better to use "using namespace std;" after header file.While loop is used for repeatation that we do not know the limit how times the loop will continue.It is better to use control statements such as" if , if else or switch case" for conditions.

[rattler]

Any help? "Wrong answer"

include

include

//void read();
using namespace std;

int main() {

//read();

int number=0;
std::fstream in;
std::fstream out;
in.open("data.txt");
out.open("output.txt");

if (in.good()) {
	in >> number;

	while (number != 42) {
		out << number << endl;
		in >> number;
		
	}
}



return 0;

}

[amit_phulera]

This code gets accepted on CodeChef but it's saying "Wrong Answer" on SPOJ. If anyone can figure out what am I doing wrong. Help would be greatly appreciated.
`#include < iostream >
using namespace std;

int main() {
int x;
while(cin>>x ){

	if(x==42)
		break;
	cout<<x<<endl;

}
return 0;

} `

[ndha]

Can someone say what is the problem here?
Judge shows wrong answer:

#include<iostream>
using namespace std;

int main (){
	int number;
	freopen("index.txt","r", stdin );
	cin>>number;
	int P[number-1];
	for(int i=0;i<number;i++){
		cin>>P[i];
		if(P[i] == 42)
			break;
			cout<<P[i]<<'\n';
	}
}

[saurabh589]

hi what is the problem in this code.?
#include
using namespace std ;
int main()
{
int n[5],i;
for (i=0; i<=5;i++){
cin>>n[i];
}
for (i=0; i<=5;i++){
if (n[i]==42)
break;
else{
cout<<n[i]<<endl;
}
}
return 0;

}

[syfe]

Why it’s wrong?
#include
using namespace std;

int main()
{
int i,j,k,l,num[1000];
cout<<“Enter how many numbers you want to add:”;
cin>>i;
for(j=0;j<i;j++){
cin>>num[j];
if(num[j]==42){
break;
}
cout<<num[j]<<endl;
}
}

[simes]

Enter how many numbers you want to add:

This text doesn’t appear in the sample output given in the problem, so you shouldn’t write it either.

The problem doesn’t say there will be 1000 numbers or or fewer, so it’d be better if you didn’t assume it.

[gennadie_0108]

#include<iostream>
#include <list>
#include <iterator>
using namespace std;

void outputNumber(list <int> g){
    list <int> :: iterator it;
    for(it = g.begin(); it != g.end(); ++it) {
        if(*it==42){
            break;
        }else{
            cout<<*it<<endl;
        }
    }
}

int main(){
    int myints[] = {1,2,88,42,99};
    std::list<int> testInputs (myints, myints + sizeof(myints) / sizeof(int) );
    std::cout << "The contents of the tested inputs are: ";
  for (std::list<int>::iterator it = testInputs.begin(); it != testInputs.end(); it++)
    std::cout << *it << ' ';

  std::cout << '\n';
    outputNumber(testInputs);
    return 0;

}

my codes have output the correct answers, but the compiler does not accept it…

[ukartikey]

The problem in the code lies in the while loop condition , i am not able to end taking the input, help!!
#include
#include<stdlib.h>
using namespace std;
int main()
{
int x[100],n=0,i=0;
while(cin>>n)
{

	x[i]=n;
	i++;
}
for(int j=0;j<=i;j++)
{
	if(x[j]==42) exit(15);
	else
	std::cout<<x[j]<<endl;
}
return 0;

}

[bibekdhkl]

your solution won’t give the expected output

[bibekdhkl]

I did it in a simple way! Hope it becomes of some help

And cross-question for you
How can I manage memory properly in this program???

#include<stdio.h>

int main(){
      int arr[1000],i=0,n=0;
      do{
            scanf("%d",&arr[i]);
            i++;
            n++;
      }while(arr[i-1]!=42);
      for(i=0;i<(n-1);i++){
            printf("%d\n",arr[i]);
      }
      return 0;
}