Checking Whether Number is Big Endian or Little Endian

[naveenshukla]

Hello Everyone

#include <iostream>
#include <cstdio>
using namespace std;
int main()
{
int num = 1;
if(*(char *)&num == 1)
{
cout << *(char *)&num << endl; 
printf("\nLittle-Endian\n");
}
else
{
printf("Big-Endian\n");
}
}

This program is printing Little-Endian but not displaying 1 ( from cout ). It is printing 1 if ( used printf )

Please help me out.Thanx in advance

[leppyr64]

Why can't you use cout << num << endl;

[naveenshukla]

yeah we can use cout << num << endl; But actually i want to print the data in one byte.It's not like that i am interested in printing 1 only.

[leppyr64]

The issue is the datatype of :
*(char *)&num

It's not an int so it won't print 1. Cast it as an int and it will.