Jun 2020
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Jun 2020
Jun 2020
sk7175
Jun '20

#include<stdio.h>
int main()
{int n,i,a[10000],c[10000],j;
scanf("%d",&n);
if(n<=1000)
{
for(i=0;i<2n;i++)
{
scanf("%d",&a[i]);
}
for(j=0,i=0;i<2n,j<n;i=2*j+2,j++)
{
c[j]=(a[i]*a[i+1]);
}
for(i=0;i<n;i++)
printf("%d\n",c[i]);
return 0;
}
}

  • created

    Jun '20

  • last reply

    Jun '20
  • 3

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simes
Jun '20

No need to start a new topic, replying the the previous one would have done.

Why do you think increasing the number of elements in a and c would fix the problem? What do you hold in these arrays?

Try this test case

1
123456789012345678901234567890 123456789012345678901234567890

sk7175
Jun '20

Ya! you are right I did a wrong thing. Sooo… what should i do increase individual capacity of units in array to satisfy problem need

simes
Jun '20

Use some structure capable of holding 10000 digits, such as a string, or byte array. You’ll then need to create a multiplication function to work with that structure.