Help in quality

[mido22_sof]

i have time limit excceds in quality
spoj.pl/problems/QUALITY/
and is for each attempt wrong i should increase time by 20 for the accepted solution or what?????????

#include<stdio.h>
int a,b,c;
int x,y,z,mot3b=20;
int equation(int sum)
{
 sum=(x-1)*mot3b+a+(y-1)*mot3b+b+(z-1)*mot3b+c;
}
int main()
{
    while(true)
    {
    int ahly,trika,n,m,sum,i=1;
    for(i=1;i<=2;i++)
    {
               ahly=sum;n=m;
               sum=0;m=3;
               scanf("%d",&a);
               scanf("%d",&b);
               scanf("%d",&c);
               scanf("%d",&x);
               scanf("%d",&y);
               scanf("%d",&z);
               if(a==0)
               {
               x=1;
               m--;
               }
               if(b==0)
               {
               y=1;
               m--;
               }
               if(c==0)
               {
               z=1;
               m--;
               }
               sum=equation(sum);
               trika=sum;
    } 
               printf("team 1: ""%d, %d\n",n,ahly);
               printf("team 2: ""%d, %d\n",m,trika);
 }
  // system ("pause");
    return 0;
}

[leppyr64]

Here's a test case:

1 1 1 1 1 1
1 1 1 1 1 1
1 1 1 1 1 1

[mido22_sof]

it gives me time limit excceds not wa and this test case is wrong becz we must enter the scores of two teams and u entered the scores of three teams not four teams :mrgreen:

[leppyr64]

1 - how do you expect to break out of that while(true)

2 - My test case is accurate. What makes you think there are two teams?

[mido22_sof]

u mean i should output after the score of each team and the input is eof

[leppyr64]

What does the problem statement say?

[mido22_sof]

the problem says
the three first inputs are the time of the three problems if there is 0 so the problem is not solved
for each problem solved if there is failed attempt i increase the time by 20
the input is eof so i use while(true)

[mido22_sof]

last attempt code from me is

#include<stdio.h>
#include<iostream>
using namespace std;
int main()
{
    int i=0;
    while(true)
    {
    i++;
    long long m,sum=0;
    long long arr[6];
    long long x;
     for(x=0;x<6;x++)
     {
      scanf("%d",&arr[x]);
     }
      m=3;
     for(x=0;x<3;x++)
     {
      int y=arr[x];
      if(y==0)
      {
       int z=arr[x+3];
       arr[x+3]=1;
       m--;
      }
     }
     sum=0;          
     for(x=3;x<6;x++)
     {
      int y=arr[x];
      int z=arr[x-3];
      sum+=(y-1)*20+z;
     } 
      printf("team %d: ""%lld, %lld\n",i,m,sum);
   }
    return 0;
}

[TripleM_sof]

A while(true) loop will never exit. Ever.

[udit_iiita]

This is my code but i am getting wa. Plz help me

#include<iostream>
#include<vector>
#include<sstream>
#include<string>
using namespace std;
int main()
{
	int a[3],b[3],so,p,n=1,i;
	string s;
	stringstream str;
	while(getline(cin,s))
	{
		so=0;
		p=0;
		str<<s;
		for(i=0;i<3;i++)
		{
			str>>a[i];
			so+=a[i];
		}
		for(i=0;i<3;i++)
		{
			str>>b[i];
			if(a[i]!=0)
			{
				p+=b[i];
			}
		}
		cout<<"team "<<n<<": "<<p<<", "<<so<<endl;
		n++;
		str.clear();
	}		
	return 0;
}

[TripleM_sof]

You clearly haven't read the problem statement properly. Read it again.

[leppyr64]

[Beaten] Ditto to TripleM

[blunder]

the code seems easy, still i'm getting WA. Here is the code,
as i get it , in every input there'll be 6 integers the first 3 are time taken to solve a problem so they simply add to the total time.
The remaining 3 integers are no. of attempts to solve a problem. If solving time for a problem is zero we do not consider it . but if the solving time is non-zero then we add (no.of.attempts - 1)2060 to the total time .

in the end we print the and in the format given , with computed values being no. of questions solved (0 or 1 or 2 or 3 ) and the total time as computed .

my code is

 got AC

please let me know if i'm missing anything