Help with LASTDIG

[drewsalt]

Hello all,

I know I make a lot of threads, but I'm eager to learn python . Plus I'm gone on vacation next week, so you won't have to put up with me anymore .
I'm doing some simple problems to help expand my grasp on python. Right now I'm attempting LASTDIG.
I've searched Google, and sadly it doesn't answer my query for some reason How can I get 2 variables on the same line?

my code so far

n = input()
i = 0
while (i < n):
    i += 1
    a = input()
    b = input()
    if a == 0 & b == 0:
        print "1"
    else:
        bignum = a ** b
        for x in range(1,1000000):
            lastdig = bignum % 10
            if lastdig < 10:
                break
                print lastdig

[numerix]

You really (really!) should go through the official python tutorial: http://docs.python.org/tutorial/index.html
There is a good printable version - so take it for vacation ....

To read more than one value from one line you can use raw_input() to get a string and than split the string using the correct string-method (look it up) and finally convert it into int.

But even if you have done this: Your approach will not work (in time) ...

[drewsalt]

alright, I'll give it a read. Thanks numerix. Seems somewhat restrictive that I can't just do something like a,b = input()

[TripleM_sof]

PS - to solve this problem you don't need anything more than normal 32 bit integers.

[drewsalt]

oh right! I vaguely remember someone telling me once that you can mod a number as you raise it to an exponent...

something like this (in C++)

for (int i = 1; i < 10; i++)
{
int num;
num = pow(num,i);
num %= 10;
}
cout << num << endl;

right?