I have only one doubt now.
Can i give the input sequence like 88 1 99 or 99 55 1 (small number followed by bigger number)..??
if not then y??

Thanks in Advance

Yes those are legal input. The numbers can be in any order. The only requirement is that they be only one or two digits and the input must contain a 42.

Know that you do not choose the input that the judge will use. Your solution must work for all possible input that the judge will give you.

Can i know the output for the following inputs(asking only for my clarity...don't mind.... )

1.) 1 12 453 32 45 67 89 987 42
2.) 123 123 123 42
3.)98 56 45 34 23 19 12 67 89 123 454 87 90 1 42

Thanks in Advance

None of those test cases are valid. The judge will not provide invalid test cases.

i wrote the following code
and in my terminal im getting the desired output but for some reason in the SPOJ its showing wrong answer
please help !! im net to SPOJ;

#include<stdio.h>
#include<stdlib.h>
int main()
{
  int a;
  scanf("%d",&a);
  while(a>0&&a!=42)
  {
    printf("%d",a);
    scanf("%d",&a);
  }
  return 0;
}

I got the same output as noix by implementing the following code but i get 'wrong answer' when i submit it on spoj please help me out
The Code:

#include<stdio.h>
int main()
{
    int a=1;
    while(a>0)
    {
        scanf("%d",&a);
        if(a != 42)
            printf("%d\n",a);
        else
            break;
    }
}

The Code When ran in ideone gave same result!

http://ideone.com/jKSYau4
http://ideone.com/XyJUag9

Why are you exiting your loop if a is zero?

Thanks A lot that solved the problem the solution was accepted!

I just can't figure put what is the problem with my code -

#include<stdio.h>
int main()
{
	int i, k[5];
    i=0;

while(i != 5)
{
scanf("%d", &k[i]);
i++;

}

i=0;

while (i !=5 )
{
	printf("%d", k[i]);
	i++;
	
	if( k[i] < k[i-1])
	{break;}
	else{printf("\n");}

}


return 0;
}

Thank you.

What problem are you trying to solve? I hope it's not TEST.

spoj.com/problems/TEST/65

Why is my source code not accepted even though the expected output is obtained?

#include <stdio.h>
int main(void){
	int x;
	for(;;)
	{
		scanf("%d",&x);
		if (x>0&&x!=42)
			printf("%d\n",x);
		else
			break;
	}
	return 0;
}

What's wrong with zero?

0
0
0
0
0
0
0
42
10
11
12

Thanks. I removed the x>0 condition and the code was accepted. But the program at the start of this thread is accepted even though it has x>0 condition. Why?

#include <stdio.h>
int main(void) {
  int x;
  for(; scanf("%d",&x) > 0 && x != 42; printf("%d\n", x));
  return 0;
}

That code is not comparing the value of x to zero. It is comparing the result from the scanf function to zero.

scanf("%d",&x) > 0

Scanf returns the number of items that it read or an error of some sort.

Here is my solution which is "accepted", 0.00 time and 2.00M used, in C language.

#include<stdio.h>
int main(void) {
    int x;
    x=0;
    while(x!=42) {
        scanf("%d",&x);
        if(x!=42)
            printf("%d\n",x);
    }
    return 0;
}

And here is a for-fun-code which solve the same problem, but closer to the example was given in the problem page. In C language too. Use in/output file.

#include<stdio.h>
#include<stdlib.h>
#define fi "d:\\program\\text\\ipTEST.txt"
#define fo "d:\\program\\text\\opTEST.txt"
struct Node {
  int data;
  struct Node *next;
};
struct Node *head;
void Inl(int); //insert last
void Clr(void); //clear
void Input(void);
void Output(void);
int main(void) {
  head=NULL;
  Input();
  Output();
  return 0;
}
void Inl(int x) {
  struct Node *t;
  t=(struct Node *)malloc(sizeof(*t));
  t->data=x;
  t->next=NULL;
  if(head==NULL)
    head=t;
  else {
    struct Node *u;
    u=head;
    while(u->next!=NULL)
      u=u->next;
    u->next=t;
  }
}
void Clr(void) {
  struct Node *prev,*curr;
  prev=head;
  head=NULL;
  curr=prev->next;
  free(prev);
  while(curr!=NULL) {
    prev=curr;
    curr=curr->next;
    free(prev);
  }
}
void Input(void) {
  FILE *f=fopen(fi,"r");
  if(!f)
    return;
  else {
    int x;
    while(!feof(f)) {
      fscanf(f,"%d",&x);
      Inl(x);
    }
    fclose(f);
  }
}
void Output(void) {
  FILE *f=fopen(fo,"w");
  if(!f)
    return;
  else {
    struct Node *t;
    t=head;
    while(t->data!=42) {
      fprintf(f,"%d\n",t->data);
      t=t->next;
    }
    Clr();
    fclose(f);
  }
}

You can find many tutorial about solution test in c language in w3school and youtube.

#include <stdio.h>
int main(void) {
	        int a;
		while(1){
		scanf("%d",&a);
		if(a== 42)
		break;
		else
		printf("%d\n",a);
		}
    return 0;
}

#include <stdio.h>
#include <stdlib.h>
int main(void)
{
   int size;
   int count=0;
   int n,i;
   int *str = (int *) malloc(sizeof(int));
   size=sizeof(int);
       
   n=0;
   do
   {
               scanf("%d",&n);
               if(count==0)
               {
                           str[0]=n;
                           ++count;
               }
               else
               {
                   size+=sizeof(int);
                   str = (int *) realloc(str, size);
                   str[count++]=n;
                   
               }
   }while(n<99);
   
   
   for(i=0;i<count;i++)
   {
                       if(str[i]==42)
                                     break;
                       else
                           printf("%d\n",str[i]);
   }

   free(str);
   return(0);
}

Hello guys, I'm new at spoj. I solved this TEST problem. It's working fine in my pc by spoj is telling me - "wrong answer". I cannot figure out what's wrong in the code. So, please help. Thanks in advance.

i have run this program on turboc++ and it gives correct result the why spoj shows wrong answer?

include

int main(void)
{
int a[20],n,i;
printf("enter the total numbers you want to enter\n");
scanf("%d",&n);
for(i=0;i<n;i++)
scanf("%d",&a[i]);
for(i=0;i<n;i++)
{
if(a[i]==42)
break;
printf("%d\n",a[i]);
}
return 0;
}