TLE on JUMP1

[dudu_sof]

1. Jumping Hands
   Problem code: JUMP1
   spoj.pl/problems/JUMP1/

Please tell me how to fix it. Thank you!

import math
pi=3.141592;
s=raw_input();
while int(s.split()[0])<>-1:
    l1=int(s.split()[0]);l2=int(s.split()[1]);l3=int(s.split()[2]);
    m1=int(s.split()[3]);m2=int(s.split()[4]);m3=int(s.split()[5]);
    s1=s.split()[6];s2=s.split()[7];
    t1=int(s1[0:2])*60*60+60*int(s1[3:5])+int(s1[6:8]);
    t2=int(s2[0:2])*60*60+60*int(s2[3:5])+int(s2[6:8]);
    u1=43200.0;u2=3600.0;u3=60.0;
    a=0.0;
    for t in range(t1,t2):
        k1=(1/(2.0*(m1+m2+m3)))*(m1*l1*math.cos(t*2*pi/u1)
            +m2*l2*math.cos(t*2*pi/u2)+m3*l3*math.cos(t*2*pi/u3));
        p1=(1/(2.0*(m1+m2+m3)))*(m1*l1*math.cos((t+1)*2*pi/u1)
            +m2*l2*math.cos((t+1)*2*pi/u2)+m3*l3*math.cos((t+1)*2*pi/u3));
        h1=abs(k1-p1);
        k2=(1/(2.0*(m1+m2+m3)))*(m1*l1*math.sin(t*2*pi/u1)
            +m2*l2*math.sin(t*2*pi/u2)+m3*l3*math.sin(t*2*pi/u3));
        p2=(1/(2.0*(m1+m2+m3)))*(m1*l1*math.sin((t+1)*2*pi/u1)
            +m2*l2*math.sin((t+1)*2*pi/u2)+m3*l3*math.sin((t+1)*2*pi/u3));
        h2=abs(k2-p2);        
        a=a+math.sqrt(h1*h1+h2*h2)
    print(a);
    s=raw_input();

[numerix]

I don't know if it will suffice to get AC, but reading input is unefficient the way you did it.
Instead of splitting one line again and again to extract the single values, you should split a line only once and then e.g. read all the needed values out of the list that contains the splitted values.

[dudu_sof]

I changed it, but still got TLE.

[numerix]

I changed it, but still got TLE.

The number of calculations has to be reduced. With some analysis of your algorithm you should be able to do so.