Solution to TEST in C++

For the sample input:

1
2
88
42
99

You have to output this:

1
2
88

You are outputting this:

input not more than 10 
numbers value '42' = stop
1. 
2. 
3. 
4. 
Stop command detected! 
Numbers to output = 3
Your output
1
2
88

These are obviously not the same. You have to output exactly what is required, not all that extra text.

Thanks. I did it whith loop, he accept. Sorry for unexperienced question.

I'm having a similar problem when submitting a solution for TEST,
I haven't included extra messages on the output , yet i got wrong answer
Here's my source code, I would appreciate any help

#include <iostream>
using namespace std;
int main()
{
	int number;
    while(true)
{
	cin >> number;
	if(number == 42)
		break;
	cout << number;
}
}

Print a whitespace(preferably '\n') after printing each number.

Thanks finally figured out I/O on the problems

Correct, you should stop when you hit 42.

You also seem to be stopping after the 11th number even if it isn't 42

Doh! Sometimes it's the obvious things that we miss.

I re-did the program using a function that calls itself, submitted it, and it was accepted.

-Oscarian

Note that a simpler method of fixing it would just be to use

for (int i=0; ; i++)

or even simpler

while (true)

rather than getting into anything complicated like a recursive function (which would cause stack errors if the input was too big).

Guys, even if any of those hideous solutions work, which is a lot to say for the very first and easiest problem ever to exist, they will land you a time of 0.01.
The I/Ostream library is SLOW as hell - depending on what you read/write to the stream, they are at LEAST 10 times slower than the standart reading/writing functions in stdio. Use stdio.h.

About the problem - try the following:

#include <stdio.h>
int main() {
  int x; //= 0 init
  scanf("%d", &x);
  while(x != 42) {
    printf("%d\n", x);
    scanf("%d", &x);
  }
  return 0;
}

There are still better approaches to the problem.

[quote="noix"]

#include <iostream>
int main(void) {
	char c, d=10;
	while(std::cin.get(c) && (c!='2' || d!='4') && std::cout.put(d)) 
		d=c;
}

[/quote]
This TEST solution is wrong, isn'it?
In case of input 8, 99, 4, 2, 10, 42, 3 it will output 8, 99.
I see that it's enough that it works for the test case, but as example answer it is not the best...

I agree it's not the best as an demonstrative example, but it does solve the problem exactly as specified. If you try the input you mentioned, you'll see it outputs the correct answer, not what you said it would.

I did

#include <stdio.h>
int main(void){
   int Input = 0;
   scanf("%d",&Input);
   while(Input != 42){
      printf("%d\n" , Input);
      scanf("%d",&Input);
      }
   return 0;
   }

simple straight forward and easy to read. Now fi I could just get my PRIME1 code to run in the alloted time...

can someone say what is the problem here.
JUDGE shows wrong answer

#include<iostream.h>
int main()
{
 int a;
 cin>>a;
 while(a!=42)
 {
             cout<<a;
             cin>>a;
 }
 return 0;
}

The correct answer for the sample input is

1
2
88

Your answer:

1288

#include<iostream>
using namespace std;
main() {
  int number=0;
  while(number!=42) {
    cin >> number;
    cout << number<< "\n";
  }
}

Please let me know what is wrong with my code.

Your solution is not correct even for the sample input.

[bbone=CPP,9]#include
using namespace std;

int main()
{
int x;
while(scanf("%d", &x) && x != 42)
printf("%d\n", x);
return 0;
}

[/bbone]

Ok i've manged to find a solution but when i submit it i got wrong answer even though it's doing what it's supposed to do

#include <iostream>
#include <stdio.h>
using namespace std;
int main()
{
	int x;
	do 
	{
		scanf ("%d", &x);
		printf (" %d \n", x);
	}
	while (x != 42);
return 0;
}

so what i'm doing wrong?

do-while is an exit control loop. it will first print the value and after that checks whether the entered value is terminating one i.e 42 or not. check you code for test cases.